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MATH1002: Mathematics
This individual assignment is due by 11:59pm Sunday 12 May 2024, via Canvas.
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Please justify your answers. Correct answers without adequate justification will not receive full
marks. A plot on its own is not considered adequate justification.
1. Let ℓ1 and ℓ2 be two lines in space defined by the parametric equations:
ℓ1 : x = 3− s, y = 4 + 5s, z = 3 + s (s ∈ R)
ℓ2 : x = 2 + t, y = −3 + t, z = −2 + 2t (t ∈ R)
Let P be the plane that contains ℓ1 and ℓ2.
(a) Find the point of intersection of ℓ1 and ℓ2.
(b) Find a general equation for P .
2. Let λ ∈ R, and consider the system of linear equations in the variables x, y, z given by
x − 5z = −4
x − λy − 2z = 2
x + 2y + λz = 2
(a) Row reduce the corresponding augmented matrix to row echelon form.
(b) Find the values of the constant λ for which the system has
(i) no solutions
(ii) exactly one solution
(iii) infinitely many solutions
3. There are 2800 MATH1061 students, and they all do one of three things on a given
night: they study linear algebra, they study calculus, or they watch netflix. We say a
MATH1061 student
is in State 1 if they study linear algebra;
is in State 2 if they study calculus; and
is in State 3 if they watch netflix.
MATH1061 students change their habits from night to night according to the following
rules:
If a student studies linear algebra one night, they have an 80% chance of studying
linear algebra the next night; a 10% chance of studying calculus the next night; and
a 10% chance of watching netflix the next night.
If a student studies calculus one night, they have a 20% chance of studying linear
algebra the next night; a 60% chance of studying calculus the next night; and a 20%
chance of watching netflix the next night.
If a student watches netflix one night, they have a 40% chance of studying linear
algebra the next night; a 40% chance of studying calculus the next night; and a 20%
chance of watching netflix the next night.
We encode the collection of probabilities of moving from one state to another in the
matrix P = (pij)3×3, where
pij is the probability of moving from State j one night to State i the next night.
2
This means P is the matrix
P =
p11 0.2 p13p21 0.6 p23
p31 0.2 p33
,
where the middle column has been filled in for you.
(a) Finish writing down the matrix P .
(b) For night n we define the vector xn =
xy
z
, where
x is the number of students in State 1;
y is the number of students in State 2; and
z is the number of students in State 3.
This means that for night n+ 1 we have
xn+1 = Pxn.
Suppose initially we have 1000 students in State 1, 1000 students in State 2, and
800 students in State 3; or in other words,
x0 =
10001000
800
.
Find the number of students in each state on night two, i.e. find x2.
(c) By considering the system
(P − I3)x = 0,
find all the vectors x that satisfy Px = x.
(d) Suppose that instead of the initial conditions in part (b), we initially have 1600
students studying linear algebra, 800 studying calculus, and 400 watching net-
flix. Find the number of students studying linear algebra, the number of students
studying calculus, and the number of students watching netflix on night n = 100.